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-3x^2-20x-54=-2x^2-10x-29
We move all terms to the left:
-3x^2-20x-54-(-2x^2-10x-29)=0
We get rid of parentheses
-3x^2+2x^2+10x-20x+29-54=0
We add all the numbers together, and all the variables
-1x^2-10x-25=0
a = -1; b = -10; c = -25;
Δ = b2-4ac
Δ = -102-4·(-1)·(-25)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{10}{-2}=-5$
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